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趣味數(shù)學(xué)問題懸賞6 初三、高一組 參考答案

2023-03-24 13:16 作者:數(shù)學(xué)只因  | 我要投稿

不知道啥是趣味數(shù)學(xué)問題懸賞看這裏

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第一題解答:

1)分情況討論

????況一:x%5Cin%20%5B%5Cspace%200%2C%5Cspace2-%5Csqrt%7B3%7D%5Cspace%5D

? ? ?????%5Cbegin%7Baligned%7D%0Af(x)%26%3D1-%7C1-2x%7C%5C%5C%0A%26%3D1-(1-2x)%5C%5C%0A%26%3D2x%5C%5C%0A%26%5Cleq2(2-%5Csqrt%7B3%7D)%5C%5C%0A%26%3D4-2%5Csqrt%7B3%7D%5C%5C%0A%26%3D(1-%5Csqrt%7B3%7D)%5E2%5C%5C%0A%26%3D(2-%5Csqrt%7B3%7D-1)%5E2%5C%5C%0A%26%5Cleq(x-1)%5E2%5C%5C%0A%26%3Dg(x)%0A%5Cend%7Baligned%7D

?????況二:x%5Cin%20(%5Cspace2-%5Csqrt%7B3%7D%2C%20%5Cspace%200.5%5Cspace%5D

? ? ?%5Cbegin%7Baligned%7D%0Af(x)%26%3D1-%7C1-2x%7C%5C%5C%0A%26%3D1-(1-2x)%5C%5C%0A%26%3D2x%5C%5C%0A%26%5Cgeq2(2-%5Csqrt%7B3%7D)%5C%5C%0A%26%3D4-2%5Csqrt%7B3%7D%5C%5C%0A%26%3D(1-%5Csqrt%7B3%7D)%5E2%5C%5C%0A%26%3D(2-%5Csqrt%7B3%7D-1)%5E2%5C%5C%0A%26%5Cgeq(x-1)%5E2%5C%5C%0A%26%3Dg(x)%0A%5Cend%7Baligned%7D

? ? ?況三:x%5Cin%20(%5Cspace%200.5%2C%20%5Cspace%201%5Cspace%5D

? ? ?%5Cbegin%7Baligned%7D%0Af(x)%26%3D1-%7C1-2x%7C%5C%5C%0A%26%3D1-(2x-1)%5C%5C%0A%26%3D2-2x%5C%5C%0A%26%5Cgeq1%2Bx%5E2-2x%5C%5C%0A%26%3D(x-1)%5E2%5C%5C%0A%26%3Dg(x)%0A%0A%5Cend%7Baligned%7D

? ? ?綜上可得?F(x) 表達(dá)式:

? ? ?%5Cbegin%7Bequation%7D%0AF(x)%3D%20%5Cleft%5C%7B%20%0A%5Cbegin%7Baligned%7D%20%0A2x%26%20%26%20x%20%5Cin%5B%5Cspace0%2C%5Cspace2-%5Csqrt%7B3%7D%5Cspace%20%5D%5C%5C%0A(x-1)%5E2%26%26x%20%5Cin(%5Cspace2-%5Csqrt%7B3%7D%2C%5Cspace1%5Cspace%20%5D%5C%5C%0A%5Cend%7Baligned%7D%0A%5Cright.%0A%0A%5Cend%7Bequation%7D

2)分情況討論

????況一:x%5Cin%20%5B%5Cspace%200%2C%5Cspace2-%5Csqrt%7B3%7D%5Cspace%5D

????注意到此時(shí)?F(x)?嚴(yán)格單調(diào)遞增

????%5Ctherefore?此時(shí)?F(x)?最大值為 F(2-%5Csqrt%7B3%7D)%3D4-2%5Csqrt%7B3%7D??

????況二:x%5Cin%20(%5Cspace%202-%5Csqrt%7B3%7D%2C%20%5Cspace%201%5Cspace%5D

????%5Cbegin%7Baligned%7D%0AF(x)%26%3D(x-1)%5E2%5C%5C%0A%26%3C(2-%5Csqrt%7B3%7D-1)%5E2%5C%5C%0A%26%3D4-2%5Csqrt%7B3%7D%0A%5Cend%7Baligned%7D

????%5Ctherefore??F(x)?最大值為?4-2%5Csqrt%7B3%7D??

3)?分情況討論

????況一:x%5Cin%20%5B%5Cspace%200%2C%5Cspace2-%5Csqrt%7B3%7D%5Cspace%5D?

????%5Cbegin%7Baligned%7D%0AF(x)%26%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C%0A2x%26%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C%0A%5Cend%7Baligned%7D

????%5Ctherefore%20x%3D%5Cfrac%7B1%7D%7B6%7D

????況二:x%5Cin%20(%5Cspace%202-%5Csqrt%7B3%7D%2C%20%5Cspace%201%5Cspace%5D

????%5Cbegin%7Baligned%7D%0AF(x)%26%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C%0A(x-1)%5E2%26%3D%5Cfrac%7B1%7D%7B3%7D%5C%5C%0A%5Cend%7Baligned%7D

?????%5Ctherefore%20x%3D%5Cfrac%7B3-%5Csqrt%7B3%7D%7D%7B3%7D%20%5Cspace%20or%20%5Cspace%20%20x%3D%5Cfrac%7B3%2B%5Csqrt%7B3%7D%7D%7B3%7D

????驗(yàn)算后得?%20x%3D%5Cfrac%7B3-%5Csqrt%7B3%7D%7D%7B3%7D%20%5Cspace%20or%20%5Cspace%20x%20%3D%20%5Cfrac%7B1%7D%7B6%7D

第二題解答:

????注意到一顆骰子最多能表示 7 個(gè)不同數(shù)位

????可得兩顆骰子可表示不超過?7%5Ccdot7%5Ccdot2%3D98

????但由于共有 99 個(gè)不同得分?jǐn)?shù)要表示,所以不能只用兩顆骰子表示所有分?jǐn)?shù)

????同理可得一顆骰子也不能表示所有分?jǐn)?shù)

????考慮三個(gè)骰子的情況,將骰子命名為 a ,?b ,?c ,并且它們的點(diǎn)數(shù)以以下方式安排

????a : 0,1,2,3,4,5

????b :?0,1,2,6,7,8

????c : 3,4,5,6,7,8

????由于 6 可用來表示 9 ,易證明可以在任兩骰子中擇一來表示 0 - 9 中的其中一個(gè)整數(shù)

????因此,易證明只需三顆骰子便可表示所有分?jǐn)?shù)

趣味數(shù)學(xué)問題懸賞6 初三、高一組 參考答案的評(píng)論 (共 條)

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