Given a?0-indexed?integer array?nums, return?the?smallest?index?i?of?nums?such that?i mod 10 == nums[i], or?-1?if such index does not exist.

x mod y?denotes the?remainder?when?x?is divided by?y.

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Example 1:

Input: nums = [0,1,2]Output: 0Explanation: i=0: 0 mod 10 = 0 == nums[0]. i=1: 1 mod 10 = 1 == nums[1]. i=2: 2 mod 10 = 2 == nums[2]. All indices have i mod 10 == nums[i], so we return the smallest index 0.

Example 2:

Input: nums = [4,3,2,1]Output: 2Explanation: i=0: 0 mod 10 = 0 != nums[0]. i=1: 1 mod 10 = 1 != nums[1]. i=2: 2 mod 10 = 2 == nums[2]. i=3: 3 mod 10 = 3 != nums[3]. 2 is the only index which has i mod 10 == nums[i].

Example 3:

Input: nums = [1,2,3,4,5,6,7,8,9,0]Output: -1Explanation: No index satisfies i mod 10 == nums[i].

用優(yōu)先隊(duì)列的話，就不需要一次排序了。會(huì)更方便的。

Easy題目；

Runtime2 ms

Beats

28.70%

Memory42.6 MB

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48.94%

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