編寫一個應(yīng)用程序求滿足1+2！+3！+……+n！<=9995的最大整數(shù)n。

package program;

public class Integer {

public static void main (String args[]) {

int sum = 0,n = 1,i = 1,s = 1;

for(i=1;i<=n;i++){

s*=i;

n++;

sum = sum+s;

if(sum>=9995){

i--;

break;

}

}

System.out.printf("求滿足1+2！+3！+……+n！<=9995的最大整數(shù)n為:%d",i);

}

}