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關(guān)于“哈希游戲”競猜系統(tǒng)開發(fā)demo

2023-06-14 10:27 作者:辰菱一絕  | 我要投稿

哈希競猜游戲的邏輯代碼可以根據(jù)不同的游戲規(guī)則和實現(xiàn)方式有所不同。在這里,注意I80開發(fā)2857技術(shù)8624過程!,我為您提供一個簡單的哈希競猜游戲的邏輯實現(xiàn),使用Python語言。 游戲規(guī)則: 1. Generate a Random sequence with a length of 10, including numbers 0-9. 2. Participants guess a number, with a minimum of 1 and a maximum of 10. 3. The computer generates a hash value, which is a random integer in the range of 0 to 20 (including 0 and 20). 4. If the number guessed by the participant is less than the computer-generated hash value, it indicates that the number guessed by the participant is too small. 5. the number guessed by the participant is greater than the computer-generated hash value, it indicates that the number guessed by the participant is too large. 6. the participant guesses the number correctly within a limited number of times, they will win. 以下是實現(xiàn)代碼: ```python import random def generate_hash(): return random.randint(0, 20) def play_hash_game(): # 生成一個長度為10的隨機數(shù)列 numbers = random.sample(range(1, 11), 10) # 生成哈希值 hash_value = generate_hash() # 提示用戶輸入猜測的數(shù)字 print("請輸入一個1到10之間的數(shù)字:") user_guess = int(input()) # 限定用戶猜測的次數(shù) num_tries = 3 while True: if user_guess < hash_value: print("猜小了,請再試一次。") elif user_guess > hash_value: print("猜大了,請再試一次。") else: print(f"恭喜您,猜對了!您猜測的數(shù)字是:{user_guess}") break user_gue

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