完成度相當(dāng)高的文件夾復(fù)制作業(yè)（支持內(nèi)嵌多個文件夾的復(fù)制）

主要考察的是遞歸，文件讀寫，os 模塊的熟練程度

接下來放上源碼，歡迎修改 src_folder 和 target_folder 的值自己嘗試

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import os

src_folder = r'D:\Code\練習(xí)\文件操作\復(fù)制文件夾\folder1'

target_folder = r'D:\Code\練習(xí)\文件操作\復(fù)制文件夾\folder2'

def copy_folder(sf, rf=''):

for x in os.listdir(sf):

path = os.path.join(sf, x)

relative_path = os.path.join(rf, x)

new_path = os.path.join(target_folder, rf, x)

if os.path.isdir(path):

if os.path.exists(new_path):

print(f'文件夾已存在：{relative_path}')

else:

print(f'創(chuàng)建文件夾：{relative_path}')

os.mkdir(new_path)

copy_folder(path, relative_path)

else:

if os.path.exists(new_path):

print(f'文件已存在：{relative_path}')

else:

print(f'復(fù)制文件：{relative_path}')

with open(path, 'rb') as read_stream:

container = read_stream.read()

with open(new_path, 'wb') as write_stream:

write_stream.write(container)

copy_folder(src_folder)

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可能直接復(fù)制筆記會出現(xiàn)問題，請下載：https://wwsc.lanzouy.com/iEor112is8ra